document.write( "Question 467415: Could you please help me with this? I have a huge final this week. I believe the answer is they are all real numbers. Am I correct? Thanks for all your help!!\r
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Algebra.Com's Answer #320714 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First, find the zeros of \"y=%28x%2B8%29%28x-13%29%28x%2B3%29\". \r
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\n" ); document.write( "\n" ); document.write( "x+8=0 or x-13=0 or x+3=0\r
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\n" ); document.write( "\n" ); document.write( "x=-8, x=13, or x=-3\r
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\n" ); document.write( "\n" ); document.write( "In ascending order, the zeros are: -8,-3,13\r
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\n" ); document.write( "\n" ); document.write( "Now in the interval , (x+8)(x-13)(x+3) is negative. Simply plug in any negative number less than -8 to see this (eg: plug in x=-10 to get (-10+8)(-10-13)(-10+3)=-322)\r
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\n" ); document.write( "\n" ); document.write( "In the interval , (x+8)(x-13)(x+3) is positive. Simply plug in any number in the interval to see this (eg: plug in x=-5 to get (-5+8)(-5-13)(-5+3)=108) \r
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\n" ); document.write( "\n" ); document.write( "In the interval , (x+8)(x-13)(x+3) is negative. Simply plug in any number in the interval to see this (eg: plug in x=0 to get (0+8)(0-13)(0+3)=-312) \r
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\n" ); document.write( "\n" ); document.write( "Finally, in the interval , (x+8)(x-13)(x+3) is positive. Simply plug in any number greater than 13 to see this (eg: plug in x=50 to get (50+8)(50-13)(50+3)=113738) \r
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\n" ); document.write( "\n" ); document.write( "So the following intervals make (x+8)(x-13)(x+3) positive: and \r
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\n" ); document.write( "\n" ); document.write( "So combine them with a union symbol to get the final answer: \r
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\n" ); document.write( "\n" ); document.write( "Here's a graph to visually confirm this\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+18%2C+-1200%2C+1000%2C+%28x%2B8%29%28x-13%29%28x%2B3%29%29+\"
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