document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=467385>Question 467385</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you please help me with this. I am not too good at finding the vertex, and graphing. Thanks so much! Huge final exam due very soon.\r<BR>\n" );
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document.write( "Find the vertex,line of symmetry, and the maximum or minimum value of f(x). Graph the function: f(x)=1/5(x+8)^2+5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #320682 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=320682\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rewrite f(x)=1/5(x+8)^2+5 as f(x)=1/5(x-(-8))^2+5\r<BR>\n" );
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document.write( "Now function is in form f(x)=a(x-h)^2+k\r<BR>\n" );
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document.write( "Vertex is (h,k). We can see that h=-8 and k=5. So the vertex is (-8,5)\r<BR>\n" );
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document.write( "The line of symmetry is the vertical line at the x coordinate of the vertex. So the line of symmetry is x = -8 (a vertical line at x=-8)\r<BR>\n" );
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document.write( "The max/min is the y value of the vertex. In this case, a=1/5, which is positive. So the y value of the vertex is a min. The min is y = 5\r<BR>\n" );
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document.write( "Graph (use a calculator or plot a series of points):\r<BR>\n" );
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