document.write( "Question 467135: You have a sector PQR where QR is the arc of the circle with center P. If the lenght of the arc QR is 6pi, and the angle formed at point P is 30 degrees, what is the area of the sector PQR?\r
\n" ); document.write( "\n" ); document.write( "The answer is 108pi.\r
\n" ); document.write( "\n" ); document.write( "I do not understand how they got this answer.\r
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Algebra.Com's Answer #320680 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Note: 30 degrees = \"30%2A%28pi%2F180%29=pi%2F6\" radians\r
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\n" ); document.write( "\n" ); document.write( "Arc length: \"L=theta%2Ar\" where \"theta\" is the central angle (that subtends, ie cuts, the arc....this angle is in radians) and r is is the radius\r
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\n" ); document.write( "\n" ); document.write( "So we're given that \"L=6pi\" and \"theta=pi%2F6\". So \r
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\n" ); document.write( "\n" ); document.write( "\"L=theta%2Ar\"\r
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\n" ); document.write( "\n" ); document.write( "\"6pi=%28pi%2F6%29%2Ar\"\r
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\n" ); document.write( "\n" ); document.write( "\"r=36\"\r
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\n" ); document.write( "\n" ); document.write( "which means that the radius of this circle is 36 units.\r
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\n" ); document.write( "\n" ); document.write( "Area of sector: \"A=%281%2F2%29r%5E2%2Atheta\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=%281%2F2%29r%5E2%2Atheta\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=%281%2F2%29%2836%29%5E2%2A%28pi%2F6%29\" plug in \"r=36\" and \"theta=pi%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=%281%2F2%29%281296%29%2A%28pi%2F6%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=%281296pi%29%2F%2812%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=108pi\"\r
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\n" ); document.write( "\n" ); document.write( "So the area is \"108pi\"
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