document.write( "Question 467146: the perimeter of a rectangle is 36 yd. the width is 18 yds less han twice the lenght. find the length and the width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #320652 by checkley79(3341)\"\" \"About 
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P=2L+2W
\n" ); document.write( "W=2L-18
\n" ); document.write( "36=2L+2(2L-18)
\n" ); document.write( "36=2L+4L-36
\n" ); document.write( "36=6L-36
\n" ); document.write( "6L=36+36
\n" ); document.write( "6L=72
\n" ); document.write( "L=72/6
\n" ); document.write( "L=12 ANS. FOR THE LENGTH.
\n" ); document.write( "W=2*12-18
\n" ); document.write( "W=24-18
\n" ); document.write( "W=6 ANS. FOR THE WIDTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "36=2*12+2*6
\n" ); document.write( "36=24+12
\n" ); document.write( "36=36
\n" ); document.write( "
\n" );