document.write( "Question 467146: the perimeter of a rectangle is 36 yd. the width is 18 yds less han twice the lenght. find the length and the width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #320652 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "W=2L-18 \n" ); document.write( "36=2L+2(2L-18) \n" ); document.write( "36=2L+4L-36 \n" ); document.write( "36=6L-36 \n" ); document.write( "6L=36+36 \n" ); document.write( "6L=72 \n" ); document.write( "L=72/6 \n" ); document.write( "L=12 ANS. FOR THE LENGTH. \n" ); document.write( "W=2*12-18 \n" ); document.write( "W=24-18 \n" ); document.write( "W=6 ANS. FOR THE WIDTH. \n" ); document.write( "PROOF: \n" ); document.write( "36=2*12+2*6 \n" ); document.write( "36=24+12 \n" ); document.write( "36=36 \n" ); document.write( " |