document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=467194>Question 467194</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angles are complementary. the sum of the measure of the first angle and half the measureof the second angle is 65.find the measures of the angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #320449 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=320449\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> two angles are complementary. the sum of the measure of the first angle and half the measure of the second angle is 65.find the measures of the angles<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Equations:<BR>\n" );
document.write( "x + y = 90<BR>\n" );
document.write( "x + (y/2) = 65<BR>\n" );
document.write( "-------------------------<BR>\n" );
document.write( "Subtract and solve for \"y\":<BR>\n" );
document.write( "(y/2) = 25<BR>\n" );
document.write( "y = 50 degrees<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Solve for \"x\":<BR>\n" );
document.write( "x + 50 = 90<BR>\n" );
document.write( "x = 40 degrees<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================= </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );