document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=467172>Question 467172</A>: <I><SPAN STYLE=\"word-break: break-all;\"> problem #1<BR>\n" );
document.write( "How many kilograms of each of a 50% silver alloy and 10% silver alloy must be mixed to obtain 24 kilograms of a 25% silver alloy?<BR>\n" );
document.write( "problem #2<BR>\n" );
document.write( "Two vats contain cream, one sample tested 8% butterfat and the other tested 16% butterfat. How much cream should be taken from each to produce a 5 liters mixture which will test 12% butterfat?<BR>\n" );
document.write( "problem #3<BR>\n" );
document.write( "How many kilograms each of a powdered detergent and a rinsing solution containing 80% of the pure rinsing solution must be mixed to make 140 kilograms of a 24% detergent?<BR>\n" );
document.write( "I'll be waiting for the answer and solution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #320442 by </B><A HREF=/tutors/aboutme.mpl?userid=Love+math><B>Love math(28)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Love+math><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=320442\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> problem #1<BR>\n" );
document.write( "How many kilograms of each of a 50% silver alloy and 10% silver alloy must be mixed to obtain 24 kilograms of a 25% silver alloy?<BR>\n" );
document.write( "let x for 50%<BR>\n" );
document.write( "let y for 10%<BR>\n" );
document.write( "   X+y= 24<BR>\n" );
document.write( "     y= 24-x<BR>\n" );
document.write( "0.50x + 0.10y =24*25<BR>\n" );
document.write( "substitution y= 24-x<BR>\n" );
document.write( "0.50x + 0.10(24-x) = 24*0.25<BR>\n" );
document.write( "0.50x + 2.4-0.10x = 24*0.25<BR>\n" );
document.write( "            0.4x  = 6<BR>\n" );
document.write( "               x=6/0.4<BR>\n" );
document.write( "               x=15<BR>\n" );
document.write( "substitution x= 15 solve for y<BR>\n" );
document.write( "            X+y= 24<BR>\n" );
document.write( "            15+y= 24<BR>\n" );
document.write( "               y =24-15<BR>\n" );
document.write( "               y =9<BR>\n" );
document.write( "nedd 15 for 50%<BR>\n" );
document.write( "need 9  for 10%\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "problem #2<BR>\n" );
document.write( "Two vats contain cream, one sample tested 8% butterfat and the other tested 16% butterfat. How much cream should be taken from each to produce a 5 liters mixture which will test 12% butterfat?\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "let x for 8%<BR>\n" );
document.write( "let y for 16%<BR>\n" );
document.write( "   X+y= 5<BR>\n" );
document.write( "     y= 5-x<BR>\n" );
document.write( "0.08x + 0.16y =5*0.12<BR>\n" );
document.write( "substitution y= 5-x<BR>\n" );
document.write( "0.08x + 0.16(5-x) =5*0.12<BR>\n" );
document.write( "0.08x + 0.8-0.16x = 0.6<BR>\n" );
document.write( "          -0.08x  = 0.6-0.8<BR>\n" );
document.write( "               x=-0.2/-0.08<BR>\n" );
document.write( "               x=2.55<BR>\n" );
document.write( "substitution x= 2.5 solve for y<BR>\n" );
document.write( "            X+y= 5<BR>\n" );
document.write( "            2.55+y= 5<BR>\n" );
document.write( "               y =5-2.5<BR>\n" );
document.write( "               y =2.5<BR>\n" );
document.write( "nedd 2.5 for 8%<BR>\n" );
document.write( "need 2.5 for 16%\r<BR>\n" );
document.write( "\n" );
document.write( "roblem #3<BR>\n" );
document.write( "How many kilograms each of a powdered detergent and a rinsing solution containing 80% of the pure rinsing solution must be mixed to make 140 kilograms of a 24% detergent?<BR>\n" );
document.write( "I'll be waiting for the answer and solution<BR>\n" );
document.write( "     140 of a 24% = <BR>\n" );
document.write( "     (140*24)/100 = 33.6<BR>\n" );
document.write( "       3.6/(140-x)= 80%<BR>\n" );
document.write( "       (140-x)*80 = 3.6*100<BR>\n" );
document.write( "     11.200 - 80x = 360<BR>\n" );
document.write( "       11.200-360 = 80x<BR>\n" );
document.write( "        10.840/80 = x<BR>\n" );
document.write( "            135.5 = x </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );