document.write( "Question 467150: how many liters of a 10% alcohol solution must be mixed with 40 L of a 50% solution to get a 40% solution \n" ); document.write( "
Algebra.Com's Answer #320431 by mananth(16946)![]() ![]() You can put this solution on YOUR website! ----------- percent ---------------- quantity \n" ); document.write( "Alcohol I 50 ---------------- 40 L \n" ); document.write( "Alcohol II 10 ---------------- x L \n" ); document.write( "Total 40 ---------------- 40 + x L \n" ); document.write( " \n" ); document.write( "50*40+10*x=40(40+x) \n" ); document.write( "2000 + 10 x = 1600 + 40 x \n" ); document.write( "10 x - 40 x = 1600 - 2000 \n" ); document.write( "-30 x = -400 \n" ); document.write( "/-30 \n" ); document.write( "x = 13.33 L 10 % Alcohol II \n" ); document.write( " \n" ); document.write( " |