document.write( "Question 467075: Determine and Solve a system of equation in three variables & define the variables:\r
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document.write( "The sum of three numbers is none.\r
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document.write( "Two times the first number plus the second number less the third number is 30.\r
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document.write( "Three times the first number subtract four times the second number plus two times the third number is -49? \n" );
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Algebra.Com's Answer #320425 by mananth(16946) You can put this solution on YOUR website! x+y+z= 0 -------------- 1 \n" ); document.write( "2x+y-z= 30 -------------- 2 \n" ); document.write( "3x-4y+2z=-49 -------------- 3 \n" ); document.write( " \n" ); document.write( "consider equation 1 &2 Eliminate y \n" ); document.write( "Multiply 1 by -1 Multiply 2 by 1 \n" ); document.write( "we get \n" ); document.write( "-x-y-z= 0 \n" ); document.write( "2x+y-z= 30 \n" ); document.write( "Add the two \n" ); document.write( "x-2z= 30 ------------- 4 \n" ); document.write( "consider equation 2 & 3 Eliminate y \n" ); document.write( "Multiply 2 by -4 \n" ); document.write( "Multiply 3 by 1 \n" ); document.write( "we get \n" ); document.write( "-8x-4y+4z=-120 \n" ); document.write( "3x-4y+2z=-49 \n" ); document.write( "Add the two \n" ); document.write( "-5x-8y+6z=-169 -------------5 5 \n" ); document.write( "Consider (4) & (5) Eliminate x \n" ); document.write( "Multiply 4 by 5 \n" ); document.write( "Multiply (5) by 1 \n" ); document.write( "we get \n" ); document.write( "5x-10z= 150 \n" ); document.write( "-5x+6z=-169 \n" ); document.write( "Add the two \n" ); document.write( "-4z=-19 \n" ); document.write( "/-4 \n" ); document.write( "z=4.75 OR 4 3/ 4 \n" ); document.write( " \n" ); document.write( "Plug the value of z in 5 \n" ); document.write( "-5x+28.5=-169 \n" ); document.write( "-5x=-197.5 \n" ); document.write( "x=39.5 OR 39 1/ 2 \n" ); document.write( "plug value of x & z in 1 \n" ); document.write( "39.5 +y+4.75 = 0 \n" ); document.write( "y=-39.5-4.75+0 \n" ); document.write( " y= -44.25 OR -44 1/4 \n" ); document.write( " \n" ); document.write( " |