document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=467090>Question 467090</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5x + 2y = -15<BR>\n" );
document.write( "2x - y = -6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #320400 by </B><A HREF=/tutors/aboutme.mpl?userid=gwendolyn><B>gwendolyn(128)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gwendolyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=gwendolyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=320400\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are several ways to solve this equation. I will show you one of them.\r<BR>\n" );
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document.write( "The first option is to isolate a variable in one of the equations, and then substitute it into the other equation. If we take the equation 2x-y=-6, we can isolate the variable 'y':\r<BR>\n" );
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document.write( "2x-y=-6<BR>\n" );
document.write( "First, we subtract '2x' from both sides<BR>\n" );
document.write( "2x-y-2x=-6-2x<BR>\n" );
document.write( "the values of '2x' cancel out on the left side of the equation<BR>\n" );
document.write( "-y=-6-2x<BR>\n" );
document.write( "Next, we multiply both sides of the equation by -1<BR>\n" );
document.write( "y=6+2x\r<BR>\n" );
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document.write( "Then, we can take this value for 'y' and plug it into the other equation:\r<BR>\n" );
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document.write( "5x+2y=-15<BR>\n" );
document.write( "We substitute in our value for 'y'<BR>\n" );
document.write( "5x+2(6+2x)=-15<BR>\n" );
document.write( "After that, we can distribute the 2<BR>\n" );
document.write( "5x+12+4x=-15<BR>\n" );
document.write( "Then, we combine the like terms in the equation<BR>\n" );
document.write( "9x=-27<BR>\n" );
document.write( "Finally, we divide both sides by three<BR>\n" );
document.write( "x=-3\r<BR>\n" );
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document.write( "After we have a value for 'x', we can substitute it into either of the original equations to find the value for 'y'.\r<BR>\n" );
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document.write( "2x-y=-6<BR>\n" );
document.write( "We substitute our value of 'x' in<BR>\n" );
document.write( "2(-3)-y=-6<BR>\n" );
document.write( "Then, we can multiply<BR>\n" );
document.write( "-6-y=-6<BR>\n" );
document.write( "We add 6 to both sides of the equation<BR>\n" );
document.write( "-y=0<BR>\n" );
document.write( "We divide both sides by -1<BR>\n" );
document.write( "y=0\r<BR>\n" );
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document.write( "So, our solution to the problem is (-3,0).<BR>\n" );
document.write( " </SPAN>\n" );
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