document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=467048>Question 467048</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Here is my problem:\r<BR>\n" );
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document.write( "Find a number such that if 5 times the number is decreased by 14, the result is twice the opposite of the number.  \r<BR>\n" );
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document.write( "I get 5X-14= but not sure how to figure out the part of twice the opposite number. Would it be 2x?\r<BR>\n" );
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document.write( "Thank you for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #320388 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=320388\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find a number such that if 5 times the number is decreased by 14, the result is twice the opposite of the number. <BR>\n" );
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document.write( "The opposite number of x is -x, so you have<BR>\n" );
document.write( "5x - 14 = 2(-x)<BR>\n" );
document.write( "5x -14 = -2x<BR>\n" );
document.write( "5x + 2x =  14<BR>\n" );
document.write( "x = 2 </SPAN>\n" );
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