document.write( "Question 467019: You invested 14,000 in two accounts paying 6% and 9% annual interest, respectively. If the total interest earned for the year $900, how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #320347 by rfer(16322)![]() ![]() ![]() You can put this solution on YOUR website! 0.06x+0.09(14000-x)=900 \n" ); document.write( "0.06x+1260-0.09x=900 \n" ); document.write( "-0.03x=-360 \n" ); document.write( "x=$12,000 at 6% \n" ); document.write( "14000-12000=$2,000 at 9% \n" ); document.write( " |