document.write( "Question 467026: Help please! I need to solve using substitution: 1/5x +1/2y=8 x+y=20 \n" ); document.write( "
Algebra.Com's Answer #320315 by stanbon(75887)\"\" \"About 
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solve using substitution:
\n" ); document.write( "1/5x +1/2y=8
\n" ); document.write( "x+y=20
\n" ); document.write( "---
\n" ); document.write( "Multiply thru the 1st equation by 10 to get rid of the fractions.
\n" ); document.write( "2x + 5y = 80
\n" ); document.write( "---
\n" ); document.write( "Substitute for \"y\" and solve for \"x\":
\n" ); document.write( "2x + 5(20-x) = 80
\n" ); document.write( "---
\n" ); document.write( "2x + 100 - 5x = 80
\n" ); document.write( "---
\n" ); document.write( "-3x = -20
\n" ); document.write( "x = 20/3
\n" ); document.write( "-----
\n" ); document.write( "Solve for \"y\";
\n" ); document.write( "x+y = 20
\n" ); document.write( "(20/3) + y = (60/3)
\n" ); document.write( "y = 40/3
\n" ); document.write( "=============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( " \n" ); document.write( "
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