document.write( "Question 467008: Please help with this question:
\n" ); document.write( "A pyramid has a rectangular base. Suppose that the edges of the base and the height of the pyramid are all doubled in length. What happens to the volume?
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Algebra.Com's Answer #320294 by Earlsdon(6294)\"\" \"About 
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Start with the formula for the volume of a rectangular pyramid:
\n" ); document.write( "\"V+=+%281%2F3%29B%2Ah\" Where B = area of the base of the pyramid (L*W) and h = its perpendicular height.
\n" ); document.write( "Let's say that the area of the base of the original pyramid is given by \"a%2Ab\" and its height is \"h\". Its volume is then:
\n" ); document.write( "\"highlight%28V%5B1%5D+=+%281%2F3%29abh%29\"
\n" ); document.write( "Now we'll double the three dimensions to \"2a\", \"2b\", and \"2h\" and find the new volume:
\n" ); document.write( "\"V%5B2%5D+=+%281%2F3%29%282a%29%282b%29%282h%29\" Simplifying this we get:
\n" ); document.write( "\"highlight_green%28V%5B2%5D+=+%281%2F3%29%288%29abh%29\"
\n" ); document.write( "As you can see, the new volume is 8 times the original volume.
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