document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=466984>Question 466984</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 38 m. If the length is 5m less than the twice its width, find the dimension of the rectangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #320286 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=320286\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width equal x m, then its length will be 2x-5 m, and half of the perimeter is represented by the equation: x+2x-5=19. Solving this equation we find the width x=8 m. Substituting x=8 we get the length, 2*8-5=11 m.\r<BR>\n" );
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document.write( "Answer:The dimensions of the rectangle are 8m and 11m. </SPAN>\n" );
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