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please help me solve this question \"if the length of perpendicular from the origin to a line is 5 units and its angle is 120 degrees then what is the equation of line?
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\n" ); document.write( "Using trigonometry terminology, rotating the perpendicular 120º places the point of intersection of the perpendicular and line in quadrant II. You are now working with a reference angle of 60º. The slope of the perpendicular=tan 60º=-√3 in quadrant II. You also have a right triangle to work with where the hypotenuse=length of the perpendicular=5, and legs=(x,y) coordinates of the intersection.
\n" ); document.write( "x=5 cos 60º=5*-1/2=-5/2=-2.5
\n" ); document.write( "y=5 sin 60º=5*√3/2=5√3/2=4.33
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\n" ); document.write( "slope of line=1/√3 (negative reciprocal of perpendicular)
\n" ); document.write( "Equation: y=x/√3+b
\n" ); document.write( "solving for b, using point of intersection (x,y) coordinates
\n" ); document.write( "4.33=-2.5/√3+b
\n" ); document.write( "b=4.33+2.5/√3=4.33+1.44=5.77
\n" ); document.write( "equation of line:
\n" ); document.write( "y=x/√3+5.77
\n" ); document.write( "see graph below as a visual check on the answer\r
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