document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=466938>Question 466938</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Car A and car B leave Halifax on the same road 1 hr apart. Car A leaves first and travels at a steady 80 km/h. How fast must car B travel to overtake car A in 4 hours? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #320260 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=320260\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = speed of car B.  If car B is to overtake car A in 4 hours, then car A must have been on the road for  4 + 1 = 5 hours.  Hence the distance traveled by car A should have been (5 hr)*(80 km/hr) = 400 km.\r<BR>\n" );
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document.write( "==> 4x = 400 ==> x = 100 km/hr, the speed of car B. </SPAN>\n" );
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