document.write( "Question 466907: How many gallons of 50% antifreeze solution must be mixed with 100 gallons of 30% antifreeze to get a mixture that is 40% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #320214 by stanbon(75887)\"\" \"About 
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How many gallons of 50% antifreeze solution must be mixed with 100 gallons of 30% antifreeze to get a mixture that is 40% antifreeze?
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\n" ); document.write( "Equation:
\n" ); document.write( "alcohol + alcohol = alcohol
\n" ); document.write( "0.50x + 0.30*100 = 0.40(x+100)
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\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "50x + 30*100 = 40x + 40*100
\n" ); document.write( "10x = 10*100
\n" ); document.write( "x = 100 gallons (amt. of 50% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H
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