document.write( "Question 466907: How many gallons of 50% antifreeze solution must be mixed with 100 gallons of 30% antifreeze to get a mixture that is 40% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #320214 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How many gallons of 50% antifreeze solution must be mixed with 100 gallons of 30% antifreeze to get a mixture that is 40% antifreeze? \n" ); document.write( "----------------------- \n" ); document.write( "Equation: \n" ); document.write( "alcohol + alcohol = alcohol \n" ); document.write( "0.50x + 0.30*100 = 0.40(x+100) \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "50x + 30*100 = 40x + 40*100 \n" ); document.write( "10x = 10*100 \n" ); document.write( "x = 100 gallons (amt. of 50% solution needed) \n" ); document.write( "================================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H \n" ); document.write( "============= \n" ); document.write( " |