document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=418776>Question 418776</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the original mixture weighed 800 pounds and was 40% slaked lime. how much of a 20% slaked lime mixture sh9ould be added to reduce the lime concentration to 36%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #320180 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=320180\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 800(.4)+m(.2)=.36(800+m)<BR>\n" );
document.write( "320+.2m=288+.36m<BR>\n" );
document.write( "32=.16m<BR>\n" );
document.write( "m=200<BR>\n" );
document.write( "You need 200 lbs of 20% lime to reduce your concentration.. </SPAN>\n" );
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