document.write( "Question 466558: six year hence a man's age will be 3 times a age of his son and 3 tears ago he was 9 times as old his son \n" ); document.write( "

Algebra.Com's Answer #320078 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Six year hence a man's age will be 3 times a age of his son and 3 tears ago he was 9 times as old his son
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\n" ); document.write( "Let m = man's age
\n" ); document.write( "Let s = son's age
\n" ); document.write( ":
\n" ); document.write( "\"six year hence a man's age will be 3 times a age of his son \"
\n" ); document.write( "m + 6 = 3(s+6)
\n" ); document.write( "m + 6 = 3s + 18
\n" ); document.write( "m = 3s + 18 - 6
\n" ); document.write( "m = 3s + 12
\n" ); document.write( ":
\n" ); document.write( "\" and 3 tears ago he was 9 times as old his son\"
\n" ); document.write( "m - 3 = 9(s-3)
\n" ); document.write( "m = 9s - 27 + 3
\n" ); document.write( "m = 9s - 24
\n" ); document.write( ":
\n" ); document.write( "Using the 1st equation, replace m with (9s-24)
\n" ); document.write( "9s - 24 = 3s + 12
\n" ); document.write( "9s - 3s = 12 + 24
\n" ); document.write( "6s = 36
\n" ); document.write( "s = $\"36%2F6\"$
\n" ); document.write( "s = 6 yrs old is the son
\n" ); document.write( ":
\n" ); document.write( "Find m
\n" ); document.write( "m = 3s + 12
\n" ); document.write( "m = 3(6) + 12
\n" ); document.write( "m = 18 + 12
\n" ); document.write( "m = 30 yrs is Dad's age
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\n" ); document.write( ":
\n" ); document.write( "Check solution in the 2nd statement
\n" ); document.write( "\" 3 years ago he was 9 times as old his son\"
\n" ); document.write( "30 - 3 = 9(6-3)
\n" ); document.write( "27 = 9(3), confirms our solutions of m=30, s=6
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