document.write( "Question 466780: For x < 2;
\n" ); document.write( "1/(|x - 2|) + 1/(|2 - x|) = ?\r
\n" ); document.write( "\n" ); document.write( "I got both terms multiplied by the denominator/denominator of the other term to get both of them to the same common denominator, mainly:
\n" ); document.write( "(|2 - x| + |x - 2|)/(|2 - x| * |x - 2|), but don't know how to proceed further. Please help
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Algebra.Com's Answer #320057 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
For x < 2;
\n" ); document.write( "1/(|x - 2|) + 1/(|2 - x|) = ?
\n" ); document.write( "I got both terms multiplied by the denominator/denominator of the other term to get both of them to the same common denominator, mainly:
\n" ); document.write( "(|2 - x| + |x - 2|)/(|2 - x| * |x - 2|), but don't know how to proceed further
\n" ); document.write( "----
\n" ); document.write( "If x < 2 |x-2| is always negative; so |2-x| = -(2-x) = x-2
\n" ); document.write( "---
\n" ); document.write( "If x < 2, |2-x| is always positive; so |2-x| = 2-x
\n" ); document.write( "----
\n" ); document.write( "So, if x < 2, 1/|x-2| + 1/|2-x|
\n" ); document.write( "--------
\n" ); document.write( "= 1/(x-2) + 1/(2-x)
\n" ); document.write( "---
\n" ); document.write( "= [2-x+x-2]/[(x-2)(2-x)]
\n" ); document.write( "---
\n" ); document.write( "= 0/[(x-2)(2-x)]
\n" ); document.write( "--
\n" ); document.write( "= 0
\n" ); document.write( "=================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( "
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