document.write( "Question 466780: For x < 2;
\n" );
document.write( "1/(|x - 2|) + 1/(|2 - x|) = ?\r
\n" );
document.write( "\n" );
document.write( "I got both terms multiplied by the denominator/denominator of the other term to get both of them to the same common denominator, mainly:
\n" );
document.write( "(|2 - x| + |x - 2|)/(|2 - x| * |x - 2|), but don't know how to proceed further. Please help \n" );
document.write( "
Algebra.Com's Answer #320057 by stanbon(75887) ![]() You can put this solution on YOUR website! For x < 2; \n" ); document.write( "1/(|x - 2|) + 1/(|2 - x|) = ? \n" ); document.write( "I got both terms multiplied by the denominator/denominator of the other term to get both of them to the same common denominator, mainly: \n" ); document.write( "(|2 - x| + |x - 2|)/(|2 - x| * |x - 2|), but don't know how to proceed further \n" ); document.write( "---- \n" ); document.write( "If x < 2 |x-2| is always negative; so |2-x| = -(2-x) = x-2 \n" ); document.write( "--- \n" ); document.write( "If x < 2, |2-x| is always positive; so |2-x| = 2-x \n" ); document.write( "---- \n" ); document.write( "So, if x < 2, 1/|x-2| + 1/|2-x| \n" ); document.write( "-------- \n" ); document.write( "= 1/(x-2) + 1/(2-x) \n" ); document.write( "--- \n" ); document.write( "= [2-x+x-2]/[(x-2)(2-x)] \n" ); document.write( "--- \n" ); document.write( "= 0/[(x-2)(2-x)] \n" ); document.write( "-- \n" ); document.write( "= 0 \n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |