document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=466748>Question 466748</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Out of 8 persons in a group find tha number of ways of selecting 3 persons and also tha number of way of arranging these 3 selected persons in a row </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #320055 by </B><A HREF=/tutors/aboutme.mpl?userid=kmc0204><B>kmc0204(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kmc0204><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=320055\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Combinations are when order doesnt matter, permutations are when order does matter.  So the number of ways of selecting 3 people is when order does not matter, because they will still be the same people. so its 8P3 on the graphing calculator which equals 336.  The number of ways of arranging these selected three people is a combination, because order does matter, therefore its 8C3 which equals 56 </SPAN>\n" );
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