document.write( "Question 466759: A relay race required runners to run from Point A to Point B and then back to point A. the distance from A to B = 22km.\r
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document.write( "On the return trip (Point B to Point A) the runners average speed decreased by (1.2km/hr). \r
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document.write( "If the relay took 10.5 hours to complete, what was the average speed from Point A to Point B.
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Algebra.Com's Answer #320051 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A relay race required runners to run from Point A to Point B and then back to point A. the distance from A to B = 22km.\r \n" ); document.write( "\n" ); document.write( "On the return trip (Point B to Point A) the runners average speed decreased by (1.2km/hr). \r \n" ); document.write( "\n" ); document.write( "If the relay took 10.5 hours to complete, what was the average speed from Point A to Point B. \n" ); document.write( ": \n" ); document.write( "Let s = av speed from Point A to B \n" ); document.write( ": \n" ); document.write( "It says,\"On the return trip (Point B to Point A) the runners average speed decreased by (1.2km/hr).\" therefore: \n" ); document.write( "(s-1.2) = return trip speed (B to A) \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( " \n" ); document.write( "; \n" ); document.write( "Multiply by s(s-1.2), results: \n" ); document.write( "22(s-1.2) + 22s = 10.5s(s-1.2) \n" ); document.write( ": \n" ); document.write( "22s - 26.4 + 22s = 10.5s^2 - 12.6s \n" ); document.write( ": \n" ); document.write( "44s - 26.4 = 10.5s^2 - 12.6s \n" ); document.write( ": \n" ); document.write( "0 = 10.5s^2 - 12.6s - 44s + 26.4 \n" ); document.write( ": \n" ); document.write( "A quadratic equation \n" ); document.write( "10.5s^2 - 56.6s + 26.4 = 0 \n" ); document.write( "; \n" ); document.write( "Multiply by 10 to get rid of the decimals \n" ); document.write( "105s^2 - 566s + 264 = 0 \n" ); document.write( ": \n" ); document.write( "Use the quadratic formula to solve this \n" ); document.write( " \n" ); document.write( "a=105, b=-566, c=264, s=x \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Two solutions, but only this one will make sense \n" ); document.write( " \n" ); document.write( "s = \n" ); document.write( "s = 4.87 km/hr, av speed from A to B \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this by finding the times \n" ); document.write( "22/4.87 = 4.5 hrs \n" ); document.write( "22/3.67 = 6.0 hrs \n" ); document.write( "----------------- \n" ); document.write( "tot time: 10.5 hrs, confirms our solution \n" ); document.write( " |