document.write( "Question 466762: 2^(3x+1)= 3^(x-2)
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\n" ); document.write( "I get log base 2^3^(x-2)= 3x+1 and I am stuck after this. Any suggestions?
\n" ); document.write( "Thanks so much
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Algebra.Com's Answer #320050 by ccs2011(207)\"\" \"About 
You can put this solution on YOUR website!
Good so far, took log of both sides
\n" ); document.write( "For simplicity sake, when I use log i am using log base 2.
\n" ); document.write( "\"3x+%2B+1+=+log+%283%5E%28x-2%29%29\"
\n" ); document.write( "From here you need to use the following log property:
\n" ); document.write( "\"log+x%5En+=+n%2Alog+x\"
\n" ); document.write( "This will get the variable x out of the exponent
\n" ); document.write( "\"3x+%2B+1+=+%28x-2%29log+3\"
\n" ); document.write( "Distribute right side
\n" ); document.write( "\"3x+%2B+1+=+xlog+3+-+2log+3\"
\n" ); document.write( "Get x's on left side, constants on right
\n" ); document.write( "\"3x+-+xlog+3+=+-2log+3+-+1\"
\n" ); document.write( "Factor out the x on left, and factor out negative on right
\n" ); document.write( "\"x%283+-+log+3%29+=+-%282log+3+%2B+1%29\"
\n" ); document.write( "Divide by (3 - log 3) on both sides
\n" ); document.write( "\"+x+=+-%282log+3+%2B+1%29%2F%283+-+log+3%29\"
\n" ); document.write( "If you use your calculator this is approximately
\n" ); document.write( "\"x+=+-2.95\"
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