document.write( "Question 466762: 2^(3x+1)= 3^(x-2)
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document.write( "I get log base 2^3^(x-2)= 3x+1 and I am stuck after this. Any suggestions?
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document.write( "Thanks so much \n" );
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Algebra.Com's Answer #320050 by ccs2011(207)![]() ![]() You can put this solution on YOUR website! Good so far, took log of both sides \n" ); document.write( "For simplicity sake, when I use log i am using log base 2. \n" ); document.write( " \n" ); document.write( "From here you need to use the following log property: \n" ); document.write( " \n" ); document.write( "This will get the variable x out of the exponent \n" ); document.write( " \n" ); document.write( "Distribute right side \n" ); document.write( " \n" ); document.write( "Get x's on left side, constants on right \n" ); document.write( " \n" ); document.write( "Factor out the x on left, and factor out negative on right \n" ); document.write( " \n" ); document.write( "Divide by (3 - log 3) on both sides \n" ); document.write( " \n" ); document.write( "If you use your calculator this is approximately \n" ); document.write( " |