document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=466762>Question 466762</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2^(3x+1)= 3^(x-2) <BR>\n" );
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document.write( "I get log base 2^3^(x-2)= 3x+1 and I am stuck after this. Any suggestions? <BR>\n" );
document.write( "Thanks so much  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #320047 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=320047\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2^(3x+1)= 3^(x-2) <BR>\n" );
document.write( "(3x+1)*log(2) = (x-2)*log(3)<BR>\n" );
document.write( "3x*log(2) + log(2) = x*log(3) - 2log(3)<BR>\n" );
document.write( "x*log(8) - x*log(3) = -log(2) - log(9)<BR>\n" );
document.write( "x*log(8/3) = -log(18)<BR>\n" );
document.write( "x = -log(18)/log(8/3)<BR>\n" );
document.write( "x =~ -2.9469<BR>\n" );
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