document.write( "Question 466750: the perimeter of a rectangle is 146 inches. The length exceeds the width by 23 inches. Find the length and the width \n" ); document.write( "
Algebra.Com's Answer #320024 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "the perimeter of a rectangle is \"P=146in\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The length \"L\" exceeds the width \"W\" by \"23in\"\r
\n" ); document.write( "\n" ); document.write( "\"L=W%2B23in\"\r
\n" ); document.write( "\n" ); document.write( "\"P=2%28L%2BW%29\"\r
\n" ); document.write( "\n" ); document.write( "\"146in=2%28L%2BW%29\"...replace \"L\" with \"W%2B23in\"\r
\n" ); document.write( "\n" ); document.write( "\"146in=2%28W%2B23in%2BW%29\"\r
\n" ); document.write( "\n" ); document.write( "\"146in%2F2=2%28W%2B23in%2BW%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"73in=2W%2B23in\"\r
\n" ); document.write( "\n" ); document.write( "\"73in-23in=2W\"\r
\n" ); document.write( "\n" ); document.write( "\"50in=2W\"\r
\n" ); document.write( "\n" ); document.write( "\"50in%2F2=W\"\r
\n" ); document.write( "\n" ); document.write( "\"W=25in\"\r
\n" ); document.write( "\n" ); document.write( "\"L=W%2B23in\"..->....\"L=25in%2B23in\".->....\"L=48in\"
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