document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=466737>Question 466737</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a couple problems I need help with.  I did the first one, I just am having a hard time with the second one.  Please help me :)\r<BR>\n" );
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document.write( "a) 2(y-1)^2 = 4(y+1)^2\r<BR>\n" );
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document.write( "b) x/3 - x/12 = -4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #320009 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=320009\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a) 2(y-1)^2 = 4(y+1)^2<BR>\n" );
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document.write( "2(y^2-2y+1) = 4(y^2+2y+1)<BR>\n" );
document.write( "Divide both sides by 2 to get:<BR>\n" );
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document.write( "y^2-2y+1 = 2y^2+4y+2<BR>\n" );
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document.write( "y^2+6y+1 = 0<BR>\n" );
document.write( "y = [-6 +- sqrt(36-4*1)]/2<BR>\n" );
document.write( "y = [-6 +- 4sqrt(2)]/2<BR>\n" );
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document.write( "y = -3+-2sqrt(2<BR>\n" );
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document.write( "b) x/3 - x/12 = -4<BR>\n" );
document.write( "Multiply thru by 12 to get:<BR>\n" );
document.write( "4x-x = -48<BR>\n" );
document.write( "3x = -48<BR>\n" );
document.write( "x = -16<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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