document.write( "Question 48285: On Monday, Bill drove to work in 50 minutes. On Tuesday, he averaged 12 miles per hour more, and it took him 9 minutes less to get to work. how far does he travel to work? \n" ); document.write( "
Algebra.Com's Answer #32000 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Bill drove to work in 50 minutes. On Tuesday, he averaged 12 miles per hour more, and it took him 9 minutes less to get to work. how far does he travel to work?\r \n" ); document.write( "\n" ); document.write( "1st Day DATA: \n" ); document.write( "time= 50 min ; rate = x mi/min ; distance=rt = 50x \n" ); document.write( "2nd Day DATA: \n" ); document.write( "time=41 min; rate=(x+(12/60)) mi/min; distance= rt = 41(x+(1/5)=41x+8.2 mi/min\r \n" ); document.write( "\n" ); document.write( "EQUATION: \n" ); document.write( "distance = distance \n" ); document.write( "50x = 41x+8.2 \n" ); document.write( "9x = 8.2 \n" ); document.write( "x= 0.91111 mi/min \n" ); document.write( "50x=45.56 miles\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |