document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=466712>Question 466712</A>: <I><SPAN STYLE=\"word-break: break-all;\"> lindsey hires a plumber who charges $120 per visit plus $55 per hour. the plumber's bill costs $154.<BR>\n" );
document.write( "a) write a linear equation to represent this situation. let x be the number of hours the plumber stayed.<BR>\n" );
document.write( "b) solve the linear equation to determine the length of the plumbers visit\r<BR>\n" );
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document.write( "how do you work out the length of time that the plumber stayed. the answer is 37 minutes but i'm unsure of how to reach this answer.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #319994 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=319994\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 154 = 120 +55x<BR>\n" );
document.write( "154-120=55x<BR>\n" );
document.write( "34=55x<BR>\n" );
document.write( "34/55= x\r<BR>\n" );
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document.write( "x= 34/55 hours\r<BR>\n" );
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document.write( "(34/55) *60= 37 minutes </SPAN>\n" );
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