document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=466700>Question 466700</A>: <I><SPAN STYLE=\"word-break: break-all;\"> linear equation by substitution method<BR>\n" );
document.write( "x=2y+1<BR>\n" );
document.write( "3x-y=13 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #319992 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=319992\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Substitute x = 2y+1 in the equation 3x-y = 13\r<BR>\n" );
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document.write( "3(2y+1) - y  = 13<BR>\n" );
document.write( "6y+3 - y = 13<BR>\n" );
document.write( "5y = 10<BR>\n" );
document.write( "y = 2\r<BR>\n" );
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document.write( "substitute y = 2 in <BR>\n" );
document.write( "x = 2y+1<BR>\n" );
document.write( "x = 2(2) + 1<BR>\n" );
document.write( "x = 5\r<BR>\n" );
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document.write( "Answer: y = 2<BR>\n" );
document.write( "        x = 5<BR>\n" );
document.write( " </SPAN>\n" );
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