document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=466716>Question 466716</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary. The measure of the smaller angle is one- half of the measure of the greater angle. Find the measure of the greater angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #319991 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=319991\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the measure of the smaller angle<BR>\n" );
document.write( "180-x = the measure of the greater angle\r<BR>\n" );
document.write( "\n" );
document.write( "x = (1/2)(180-x)<BR>\n" );
document.write( "2x = 180 - x<BR>\n" );
document.write( "3x = 180<BR>\n" );
document.write( "x = 60\r<BR>\n" );
document.write( "\n" );
document.write( "Greater angle = 180 - x = 180 - 60 = 120\r<BR>\n" );
document.write( "\n" );
document.write( "The measure of the greater angle is 120 degrees.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );