document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=466695>Question 466695</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the solve for unknwon: log^3 (2X + 1) = 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #319976 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=319976\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log^3 (2X + 1) = 1<BR>\n" );
document.write( "convert to exponential form: Base(3) raised to log of number(1)=number(2x+1)<BR>\n" );
document.write( "3^1=2x+1=3<BR>\n" );
document.write( "2x=2<BR>\n" );
document.write( "x=1 </SPAN>\n" );
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