document.write( "Question 466681: Hello. Can you please help me fully factorize these:\r
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Algebra.Com's Answer #319965 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "You're studying factoring the difference of two squares\r\n" );
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document.write( "    A² - B² = (A - B)(A + B)\r\n" );
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document.write( "1.    3x² - 3(x+2)²\r\n" );
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document.write( "First take out the common factor 3, using []'s\r\n" );
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document.write( "  3[x² - (x+2)²]   \r\n" );
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document.write( "Now factor the expression in the []'s as the difference \r\n" );
document.write( "of two squares:\r\n" );
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document.write( " 3[x - (x+2)][x + (x+2)]\r\n" );
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document.write( "Simplify:\r\n" );
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document.write( " 3[x - x - 2][x + x + 2]\r\n" );
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document.write( " 3[-2][2x+2]\r\n" );
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document.write( "Multiply the 3 by the -2 and also take out common\r\n" );
document.write( "factor 2\r\n" );
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document.write( "   -6[2(x+1)] \r\n" );
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document.write( "    -12(x+1)\r\n" );
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document.write( "That's it.\r\n" );
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document.write( "2.    12x²-27(3+x)²\r\n" );
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document.write( "   First take out the common factor 3, using []'s\r\n" );
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document.write( "  3[4x² - 9(3+x)²]   \r\n" );
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document.write( "Now factor the expression in the []'s as the difference \r\n" );
document.write( "of two squares:\r\n" );
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document.write( " 3[2x - 3(3+x)][2x + 3(3+x)]\r\n" );
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document.write( "Simplify:\r\n" );
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document.write( " 3[2x - 9 - 3x][2x + 9 + 3x]\r\n" );
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document.write( " 3[-x - 9][5x + 9]\r\n" );
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document.write( "Take out common factor -1 in [-x - 9]\r\n" );
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document.write( " 3(-1)[x + 9][5x + 9]\r\n" );
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document.write( "   -3(x + 9)(5x + 9)\r\n" );
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document.write( "That's it.\r\n" );
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document.write( "Edwin
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