document.write( "Question 466432: i seriously need some help with this problem! in 1993, the life expectancy of males in a certain country was 66.8 years. in 2000, it was 70.4 years. let E represent the life expectancy in year t and let t represent the number of years since 1993.\r
\n" ); document.write( "\n" ); document.write( "the linear function that fits the data is E(t) = ?t + ?\r
\n" ); document.write( "\n" ); document.write( "use the function to predict the life expectancy of males in 2003.
\n" ); document.write( "E(10) = ?
\n" ); document.write( "

Algebra.Com's Answer #319925 by ankor@dixie-net.com(22740)\"\" \"About 
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In 1993, the life expectancy of males in a certain country was 66.8 years.
\n" ); document.write( " in 2000, it was 70.4 years.
\n" ); document.write( " let E represent the life expectancy in year t and let t represent the number of years since 1993.
\n" ); document.write( ":
\n" ); document.write( "Find the slope
\n" ); document.write( "In 1993; x1=0 and y1=66.8
\n" ); document.write( "In 2000; x2=7 and y2=70.4
\n" ); document.write( ":
\n" ); document.write( "Find the slope (m) using the slope equation: m = \"%28y2-y1%29%2F%28x2-x1%29\"
\n" ); document.write( "m = \"%2870.4-66.8%29%2F%287+-+0%29%29\" = \"%283.6%29%2F%287%29\" =
\n" ); document.write( ":
\n" ); document.write( "Use the point/slope formula to write the equation; y - y1 = m(x - x1)
\n" ); document.write( "y - 66.8 = \"3.6%2F7\"(x - 0)
\n" ); document.write( "y = \"3.6%2F7\"x + 66.8
\n" ); document.write( ":
\n" ); document.write( "therefore:
\n" ); document.write( "The Linear function E(t) that fits the data is.
\n" ); document.write( "E(t)= \"3.6%2F7\"t + 66.8
\n" ); document.write( ":
\n" ); document.write( "Use the Function to predict the life expectancy of males in 2003.
\n" ); document.write( "This means t=10; substitute 10 for t in the equation
\n" ); document.write( "E(10)= \"3.6%2F7\"(10) + 66.8
\n" ); document.write( "E(10)= 5.1 + 66.8
\n" ); document.write( "E(10)~ 72 yrs is the life expectancy in 2003
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