document.write( "Question 466563: Hello,
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document.write( "I have a question I need help answering. Your time is appreciated.
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document.write( "In Jose's coin jar there is a collection of nickels, dimes, and quarters which totals $4.05. There are twice as many quarters as nickels and 8 more dimes than nickels. How many coins of each kind are there? \n" );
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Algebra.Com's Answer #319914 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! coin jar there is a collection of nickels, dimes, and quarters which totals $4.05. \n" ); document.write( " There are twice as many quarters as nickels and 8 more dimes than nickels. \n" ); document.write( " How many coins of each kind are there? \n" ); document.write( ": \n" ); document.write( "Let n = no.of nickel \n" ); document.write( "Let d = no. of dimes \n" ); document.write( "let q = no. of quarters \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement: \n" ); document.write( ": \n" ); document.write( "\"coin jar there is a collection of nickels, dimes, and quarters which totals $4.05.\" \n" ); document.write( ".05n + .10d + .25q = 4.05 \n" ); document.write( ": \n" ); document.write( "\"There are twice as many quarters as nickels\" \n" ); document.write( "q = 2n \n" ); document.write( ": \n" ); document.write( "\"and 8 more dimes than nickels.\" \n" ); document.write( "d = (n+8) \n" ); document.write( ": \n" ); document.write( "In the 1st equation, replace q with 2n, replace d with (n+8) \n" ); document.write( ".05n + .10(n+8) + .25(2n) = 4.05 \n" ); document.write( ".05n + .10n + .8 + .50n = 4.05 \n" ); document.write( ".05n + .10n + .50n = 4.05 - 80 \n" ); document.write( ".65n = 3.25 \n" ); document.write( "n = \n" ); document.write( "n = 5 nickels \n" ); document.write( ": \n" ); document.write( "I'll let you find d and q, check solutions in the total$ equation.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |