document.write( "Question 466638: How many liters (L) of a 20% alcohol solution must be mixed with 60 L of a 90% alcohol solution to get a 50% alcohol solution? \n" ); document.write( "
Algebra.Com's Answer #319907 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! How many liters (L) of a 20% alcohol solution must be mixed with 60 L of a 90% alcohol solution to get a 50% alcohol solution? \n" ); document.write( "... \n" ); document.write( "x=liters of 20% alcohol solution to be mixed with 60 liters of 90% alcohol solution. \n" ); document.write( "x+60 =liters of 50% alcohol solution \n" ); document.write( "20%x+90%(60)=50%(x+60) \n" ); document.write( ".2x+54=.5x+30 \n" ); document.write( ".3x=24 \n" ); document.write( "x=80 \n" ); document.write( "ans: \n" ); document.write( "80 liters of a 20% alcohol solution must be mixed with 60 L of a 90% alcohol solution to get a 50% alcohol solution. \n" ); document.write( " |