document.write( "Question 466638: How many liters (L) of a 20% alcohol solution must be mixed with 60 L of a 90% alcohol solution to get a 50% alcohol solution? \n" ); document.write( "
Algebra.Com's Answer #319907 by lwsshak3(11628)\"\" \"About 
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How many liters (L) of a 20% alcohol solution must be mixed with 60 L of a 90% alcohol solution to get a 50% alcohol solution?
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\n" ); document.write( "x=liters of 20% alcohol solution to be mixed with 60 liters of 90% alcohol solution.
\n" ); document.write( "x+60 =liters of 50% alcohol solution
\n" ); document.write( "20%x+90%(60)=50%(x+60)
\n" ); document.write( ".2x+54=.5x+30
\n" ); document.write( ".3x=24
\n" ); document.write( "x=80
\n" ); document.write( "ans:
\n" ); document.write( "80 liters of a 20% alcohol solution must be mixed with 60 L of a 90% alcohol solution to get a 50% alcohol solution.
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