document.write( "Question 466550: heather is twice as old as armida while kaye is 35 years youner than heather. if 1/2 the age ofarmida 5 years ago , and 1/3 of the age of heathr 10 years from now is twice the age of kaye, how old is kaye now?
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Algebra.Com's Answer #319895 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Heather is twice as old as Armida while Kaye is 35 years younger than Heather. \n" ); document.write( "If 1/2 the age of Armida 5 years ago, and 1/3 of the age of Heather 10 years from now, is twice the age of Kaye, how old is Kaye. \n" ); document.write( ": \n" ); document.write( "Let h = Heather's present age \n" ); document.write( "Let a = Armida's \n" ); document.write( "Let k = Kaye's \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement: \n" ); document.write( ": \n" ); document.write( "\"Heather is twice as old as Armida\" \n" ); document.write( "h = 2a \n" ); document.write( "or \n" ); document.write( "a = .5h \n" ); document.write( ": \n" ); document.write( "\"while Kaye is 35 years younger than Heather.\" \n" ); document.write( "k = h - 35 \n" ); document.write( "or \n" ); document.write( "h = (k+35) \n" ); document.write( ": \n" ); document.write( "we need to get a in terms of k also \n" ); document.write( "a = .5(k+35) \n" ); document.write( "a = (.5k+17.5) \n" ); document.write( ": \n" ); document.write( "\"If 1/2 the age of Armida 5 years ago, and 1/3 of the age of Heather 10 years from now, is twice the age of Kaye,\" \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "multiply by 6 to clear the denominators, results: \n" ); document.write( "3(a-5) + 2(h+10) = 6(2k) \n" ); document.write( "3a - 15 + 2h + 20 = 12k \n" ); document.write( "3a + 2h + 5 = 12k \n" ); document.write( "replace h with 2a \n" ); document.write( "3a + 2(2a) + 5 = 12k \n" ); document.write( "3a + 4a + 5 = 12k \n" ); document.write( "7a + 5 = 12k \n" ); document.write( "Replace a with (.5k+17.5)) \n" ); document.write( "7(.5k+17.5) + 5 = 12k \n" ); document.write( "3.5k + 122.5 + 5 = 12k \n" ); document.write( "3.5k + 127.5 = 12k \n" ); document.write( "127.5 = 12k - 3.5k \n" ); document.write( "127.5 = 8.5k \n" ); document.write( "k = \n" ); document.write( "k = 15 yrs is Kaye's age \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "A lot of chances to make a mistake here, check this: \n" ); document.write( "h = 15 + 35 = 50 \n" ); document.write( "a = .5(50) = 25 \n" ); document.write( "Use these values in the statement: \n" ); document.write( "\"If 1/2 the age of Armida 5 years ago, and 1/3 of the age of Heather 10 years from now, is twice the age of Kaye,\" \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "10 + 20 = 30; confirms are solution\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |