document.write( "Question 466550: heather is twice as old as armida while kaye is 35 years youner than heather. if 1/2 the age ofarmida 5 years ago , and 1/3 of the age of heathr 10 years from now is twice the age of kaye, how old is kaye now?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #319895 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Heather is twice as old as Armida while Kaye is 35 years younger than Heather.
\n" ); document.write( "If 1/2 the age of Armida 5 years ago, and 1/3 of the age of Heather 10 years from now, is twice the age of Kaye, how old is Kaye.
\n" ); document.write( ":
\n" ); document.write( "Let h = Heather's present age
\n" ); document.write( "Let a = Armida's
\n" ); document.write( "Let k = Kaye's
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( ":
\n" ); document.write( "\"Heather is twice as old as Armida\"
\n" ); document.write( "h = 2a
\n" ); document.write( "or
\n" ); document.write( "a = .5h
\n" ); document.write( ":
\n" ); document.write( "\"while Kaye is 35 years younger than Heather.\"
\n" ); document.write( "k = h - 35
\n" ); document.write( "or
\n" ); document.write( "h = (k+35)
\n" ); document.write( ":
\n" ); document.write( "we need to get a in terms of k also
\n" ); document.write( "a = .5(k+35)
\n" ); document.write( "a = (.5k+17.5)
\n" ); document.write( ":
\n" ); document.write( "\"If 1/2 the age of Armida 5 years ago, and 1/3 of the age of Heather 10 years from now, is twice the age of Kaye,\"
\n" ); document.write( "\"1%2F2\"(a-5) + \"1%2F3\"(h+10) = 2k
\n" ); document.write( ":
\n" ); document.write( "multiply by 6 to clear the denominators, results:
\n" ); document.write( "3(a-5) + 2(h+10) = 6(2k)
\n" ); document.write( "3a - 15 + 2h + 20 = 12k
\n" ); document.write( "3a + 2h + 5 = 12k
\n" ); document.write( "replace h with 2a
\n" ); document.write( "3a + 2(2a) + 5 = 12k
\n" ); document.write( "3a + 4a + 5 = 12k
\n" ); document.write( "7a + 5 = 12k
\n" ); document.write( "Replace a with (.5k+17.5))
\n" ); document.write( "7(.5k+17.5) + 5 = 12k
\n" ); document.write( "3.5k + 122.5 + 5 = 12k
\n" ); document.write( "3.5k + 127.5 = 12k
\n" ); document.write( "127.5 = 12k - 3.5k
\n" ); document.write( "127.5 = 8.5k
\n" ); document.write( "k = \"127.5%2F8.5\"
\n" ); document.write( "k = 15 yrs is Kaye's age
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "A lot of chances to make a mistake here, check this:
\n" ); document.write( "h = 15 + 35 = 50
\n" ); document.write( "a = .5(50) = 25
\n" ); document.write( "Use these values in the statement:
\n" ); document.write( "\"If 1/2 the age of Armida 5 years ago, and 1/3 of the age of Heather 10 years from now, is twice the age of Kaye,\"
\n" ); document.write( "\"1%2F2\"(25-5) + \"1%2F3\"(50+10) = 2(15)
\n" ); document.write( "\"1%2F2\"(20) + \"1%2F3\"(60) = 30
\n" ); document.write( "10 + 20 = 30; confirms are solution\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );