document.write( "Question 460753: im not sure of how to solve these problems,\r
\n" ); document.write( "\n" ); document.write( "1. log3(2x-1) + log(base 3)2 = 2
\n" ); document.write( "2. 4(^3-2x = 12
\n" ); document.write( "3. 3^x = 1/81
\n" ); document.write( "4. 9^x - 6x3^x - 27 = 0\r
\n" ); document.write( "\n" ); document.write( "all working would be greatly appreciated,
\n" ); document.write( "emily.
\n" ); document.write( "

Algebra.Com's Answer #319893 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
1. log3(2x-1) + log(base 3)2 = 2
\n" ); document.write( "2. 4(^3-2x = 12
\n" ); document.write( "3. 3^x = 1/81
\n" ); document.write( "4. 9^x - 6x3^x - 27 = 0
\n" ); document.write( "..
\n" ); document.write( "1. log3(2x-1) + log(base 3)2 = 2
\n" ); document.write( "Write as single log
\n" ); document.write( "log3(2x-1)(2)=2
\n" ); document.write( "convert to exponential form:(base(3) raised to log of number(2)=number((2x-1)(2)
\n" ); document.write( "3^2=(2x-1)(2)
\n" ); document.write( "9=4x-2
\n" ); document.write( "4x=11
\n" ); document.write( "x=11/4
\n" ); document.write( "..
\n" ); document.write( "2. 4(^3-2x = 12
\n" ); document.write( "4^3-2x=12
\n" ); document.write( "64-2x=12
\n" ); document.write( "2x=64-12=52
\n" ); document.write( "x=26
\n" ); document.write( "..
\n" ); document.write( "3. 3^x = 1/81
\n" ); document.write( "3^x=1/3^4=3^-4
\n" ); document.write( "x=-4
\n" ); document.write( "..
\n" ); document.write( "4. 9^x - 6x3^x - 27 = 0
\n" ); document.write( "I believe this equation was meant to be written as follows:
\n" ); document.write( "9^x - (6)3^x - 27 = 0
\n" ); document.write( "3^2x-6*3^x-27=0
\n" ); document.write( "(3^x+3)(3^x-9)=0
\n" ); document.write( "3^x+3=0
\n" ); document.write( "3^x≠-3 (reject)
\n" ); document.write( "3^x-9=0
\n" ); document.write( "3^x=9=3^2
\n" ); document.write( "x=2
\n" ); document.write( "
\n" );