document.write( "Question 466574: Hello and thank you so much for your help.I got this function 7-6x-x^2=0 it's a parabola that crosses the x-axis on the points -7.0 and 1.0, the vertex it's at the point (-3.0,16). I need to find the equation of the axis of symmetry for this parabola. Thank you again and have a happy 4th of July. \n" ); document.write( "

Algebra.Com's Answer #319891 by nerdybill(7384) $\"\"$ $\"About$

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Hello and thank you so much for your help.I got this function 7-6x-x^2=0 it's a parabola that crosses the x-axis on the points -7.0 and 1.0, the vertex it's at the point (-3.0,16). I need to find the equation of the axis of symmetry for this parabola. Thank you again and have a happy 4th of July.
\n" ); document.write( ".
\n" ); document.write( "You can derive the axis of symmetry from the vertex and \"inspecting\" the original equation.
\n" ); document.write( "First,
\n" ); document.write( "Determine whether it is a \"vertical\" or a \"horizontal\" parabola. If your equation has a x^2 term -- it is a \"vertical\" parabola.
\n" ); document.write( "Second,
\n" ); document.write( "Once you know this, then you can simply use the x-coordinate of the vertex. So, the axis of symmetry is then
\n" ); document.write( "x = -3 (vertical line crossing the x-axis at -3)
\n" ); document.write( ".
\n" ); document.write( "Note:
\n" ); document.write( "the axis of symmetry is also derived by:
\n" ); document.write( "-b/(2a)
\n" ); document.write( "where
\n" ); document.write( "'a' and 'b' are the coefficients of the original equation \n" ); document.write( "

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