document.write( "Question 466529: an automobile director contains 8 liters of solution that 10% is antifreeze. How many liters of water must be drained and replaced with pure antifreeze to obtain a 25% antifreeze mixture? \n" ); document.write( "
Algebra.Com's Answer #319884 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! an automobile director contains 8 liters of solution that 10% is antifreeze. How many liters of water must be drained and replaced with pure antifreeze to obtain a 25% antifreeze mixture? \n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "let x=liters of 10% solution that must be drained and replaced with pure antifreeze. \n" ); document.write( "8-x =liters of remaining 10% solution \n" ); document.write( "100%x+10%(8-x)=25%(8) \n" ); document.write( "x+.8-.1x=2 \n" ); document.write( ".9x=1.2 \n" ); document.write( "x=1.33 liters \n" ); document.write( " |