document.write( "Question 466529: an automobile director contains 8 liters of solution that 10% is antifreeze. How many liters of water must be drained and replaced with pure antifreeze to obtain a 25% antifreeze mixture? \n" ); document.write( "
Algebra.Com's Answer #319884 by lwsshak3(11628)\"\" \"About 
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an automobile director contains 8 liters of solution that 10% is antifreeze. How many liters of water must be drained and replaced with pure antifreeze to obtain a 25% antifreeze mixture?
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\n" ); document.write( "\n" ); document.write( "let x=liters of 10% solution that must be drained and replaced with pure antifreeze.
\n" ); document.write( "8-x =liters of remaining 10% solution
\n" ); document.write( "100%x+10%(8-x)=25%(8)
\n" ); document.write( "x+.8-.1x=2
\n" ); document.write( ".9x=1.2
\n" ); document.write( "x=1.33 liters
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