document.write( "Question 466523: Bob is 5 times the age of his daughter Jane. In 5 years time, Bob will be 3 times Jane's age. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #319853 by Earlsdon(6294)\"\" \"About 
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Let B = Bob's present age and J = his daughter Jane's present age.
\n" ); document.write( "1) \"B+=+5J\" \"Bob is 5 times the age of his daughter Jane.\"
\n" ); document.write( "2) \"B%2B5+=+3%28J%2B5%29\" \"In 5 year's time, Bob will be 3 times Jane's age.\"
\n" ); document.write( "Into equation 2), substitute \"B+=+5J\" from equation 1) and solve for J.
\n" ); document.write( "3) \"%285J%29%2B5+=+3%28J%2B5%29\" Simplify this.
\n" ); document.write( "4) \"5J%2B5+=+3J%2B15\" Subtract 3J from both sides.
\n" ); document.write( "5) \"2J%2B5+=+15\" Subtract 5 from both sides.
\n" ); document.write( "6) \"2J+=+10\" Divide both sides by 2
\n" ); document.write( "7) \"highlight%28J+=+5%29\" Now substitute this value of J into equation 1) to find the value of B.
\n" ); document.write( "8) \"B+=+5%285%29\"
\n" ); document.write( "9) \"highlight_green%28B+=+25%29\"
\n" ); document.write( "Bob's present age is 25 and his daughter Jane's present age is 5.
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