document.write( "Question 466508: Given that $\"u+=+log%28base9%29x\"$ , find in terms of u,
\n" ); document.write( "i) $\"log%28base3%29x\"$
\n" ); document.write( "ii) $\"log%28base9%2927x\"$
\n" ); document.write( "iii) $\"log%28base2%2981\"$ \r
\n" ); document.write( "\n" ); document.write( "*Please answer as soon as possible bro. :) =) \n" ); document.write( "

Algebra.Com's Answer #319824 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
Given that $\"u+=+log%28base9%29x\"$ , find in terms of u,
\n" ); document.write( "i) $\"log%28base3%29x\"$
\n" ); document.write( "ii) $\"log%28base9%2927x\"$
\n" ); document.write( "iii) $\"log%28base2%2981\"$
\n" ); document.write( "...
\n" ); document.write( "log9(x)=u
\n" ); document.write( "exponential form:9^u=x
\n" ); document.write( "..
\n" ); document.write( "log3(x)
\n" ); document.write( "exponential form:(3^2)^u=3^2u=9^u=x
\n" ); document.write( "log3(x)=2u
\n" ); document.write( "..
\n" ); document.write( "log9(27x)
\n" ); document.write( "log9(x)+log9(27)
\n" ); document.write( "log9(x)+log9(9)+Log9(3)
\n" ); document.write( "log9(27x)=u+1+1/2=u+3/2
\n" ); document.write( "..
\n" ); document.write( "log2(81)
\n" ); document.write( "sorry, I don't know how to do this one.
\n" ); document.write( "Let me know when you find the right ans. \n" ); document.write( "

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