document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=466500>Question 466500</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man's age is 2 yrs. more than thrice his son's age. Find the ages of both if the sum of their ages is 46.. pls.. I really need them tom. <BR>\n" );
document.write( "HOPE YOU'LL help thanks a lot </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #319813 by </B><A HREF=/tutors/aboutme.mpl?userid=ccs2011><B>ccs2011(207)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ccs2011><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ccs2011><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=319813\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let A be fathers age, B be sons age:<BR>\n" );
document.write( "A = 3B + 2<BR>\n" );
document.write( "A + B = 46<BR>\n" );
document.write( "Substitute value of A in 1st equation into 2nd equation<BR>\n" );
document.write( "(3B+2) + B = 46<BR>\n" );
document.write( "Combine like terms<BR>\n" );
document.write( "4B + 2 = 46<BR>\n" );
document.write( "Subtract 2 on both sides<BR>\n" );
document.write( "4B = 44<BR>\n" );
document.write( "Divide by 4 on both sides<BR>\n" );
document.write( "B = 11<BR>\n" );
document.write( "Substitute this value into 1st equation<BR>\n" );
document.write( "A = 3(11) + 2<BR>\n" );
document.write( "A = 33 + 2<BR>\n" );
document.write( "A = 35 </SPAN>\n" );
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