document.write( "Question 466414: During the first part of a trip, a canoeist travels 59 miels at a certain speed. The canoeist travels 25 miles on the second part of the trio at a speed of 5 mph slower. The total time for the trip is 5 hrs. What was the speed of each part of the trip. \n" ); document.write( "
Algebra.Com's Answer #319786 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! During the first part of a trip, a canoeist travels 59 miles at a certain speed. \n" ); document.write( " The canoeist travels 25 miles on the second part of the trio at a speed of 5 mph slower. \n" ); document.write( " The total time for the trip is 5 hrs. What was the speed of each part of the trip. \n" ); document.write( ": \n" ); document.write( "Let s = speed on the 1st part of the trip \n" ); document.write( "then \n" ); document.write( "(s-5) = speed on the 2nd part \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( ": \n" ); document.write( "1st part time + 2nd part time = 5 hrs \n" ); document.write( " \n" ); document.write( "multiply by s(s-5), results; \n" ); document.write( "59(s-5) + 25s = 5s(s-5) \n" ); document.write( ": \n" ); document.write( "59s - 295 + 25s = 5s^2 - 25s \n" ); document.write( ": \n" ); document.write( "84s - 295 = 5s^2 - 25s \n" ); document.write( ": \n" ); document.write( "Arrange as a quadratic equation on the right \n" ); document.write( "0 = 5s^2 - 25s - 84s + 295 \n" ); document.write( ": \n" ); document.write( "5s^2 - 109s + 295 = 0 \n" ); document.write( ": \n" ); document.write( "use the quadratic formula to find s, only one solution will make sense \n" ); document.write( " |