document.write( "Question 466391: 7. Graph the following function using transformations. Find the vertical and horizontal asymptotes. State the domain and range. Submit your graph.\r
\n" ); document.write( "\n" ); document.write( "f(x)=1/(x-5)³+1 \n" ); document.write( "
Algebra.Com's Answer #319776 by lwsshak3(11628)\"\" \"About 
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Graph the following function using transformations. Find the vertical and horizontal asymptotes. State the domain and range. Submit your graph.
\n" ); document.write( "f(x)=1/(x-5)³+1
\n" ); document.write( "...
\n" ); document.write( "Horizontal Asymptote:
\n" ); document.write( "When the degree of the numerator is less than the degree of the denominator, as in this case, the horizontal asymptote is the x-axis or y=0.
\n" ); document.write( "..
\n" ); document.write( "To find the vertical asymptote set the denominator=0, then solve for x.
\n" ); document.write( "(x-5)^3+1=0
\n" ); document.write( "(x-5)^3=-1
\n" ); document.write( "Take cube root of both sides
\n" ); document.write( "x-5=-1
\n" ); document.write( "x=5-1=4
\n" ); document.write( "Vertical asymptote: x=4
\n" ); document.write( "..
\n" ); document.write( "Domain: (-∞, 4) U (4, ∞)
\n" ); document.write( "Range: (-∞, 0) U (0, ∞)
\n" ); document.write( "See the graph below as a visual check on the answer.\r
\n" ); document.write( "\n" ); document.write( "..
\n" ); document.write( "y=1/((x-5)^3+1)
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-4%2C+4%2C1%2F1%2F%28%28x-5%29%5E3%2B1%29%29+\" \n" ); document.write( "
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