document.write( "Question 48330: A solar collector is 2.5m long by 2.0m wide. It is held in place by a frame of uniform width around its outside edge. If the exposed collector area is 2.5m^2 , what is the width of the frame, to the nearest tenth of a centimeter? \n" ); document.write( "
Algebra.Com's Answer #31976 by venugopalramana(3286)\"\" \"About 
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A solar collector is 2.5m long by 2.0m wide. It is held in place by a frame of uniform width around its outside edge. If the exposed collector area is 2.5m^2 , what is the width of the frame, to the nearest tenth of a centimeter?
\n" ); document.write( "let the width of frame = x
\n" ); document.write( "length of frame=x+2.5+x=2.5+2x
\n" ); document.write( "width of frame =x+2+x=2x+2
\n" ); document.write( "area of frame & reflector assembly=(2x+2.5)(2x+2)=4x^2+9x+5
\n" ); document.write( "area of collector=2.5*2=5
\n" ); document.write( "exposed area =4x^2+9x+5-5=2.5
\n" ); document.write( "4x^2+9x-2.5=0
\n" ); document.write( "8x^2+18x-5=0
\n" ); document.write( "x={-18+sqrt(18^2+4*5*8)}/16=1/4 metre=100/4 cm = 25 cm.
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