document.write( "Question 466404: What process would I go through to find x in the following equation?
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document.write( "(log = logarithm)\r
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document.write( "log(1 + x) + log(2 + x) = 2\r
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document.write( "I have done logarithm problems before but I never really understood the way logarithm works, I just go through the sequence my book shows me to, but I have never seen a logarithm equation such as this one before. Any help will be appreciated.
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Algebra.Com's Answer #319733 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! You have to apply the \"rules for logarithms\" \n" ); document.write( "log(1 + x) + log(2 + x) = 2 \n" ); document.write( "we can rewrite the above as: \n" ); document.write( "log(1 + x)(2 + x) = 2 \n" ); document.write( "(1 + x)(2 + x) = 10^2 \n" ); document.write( "expanding left side by FOILing: \n" ); document.write( "2+3x+x^2 = 100 \n" ); document.write( "x^2+3x+2 = 100 \n" ); document.write( "x^2+3x-98 = 0 \n" ); document.write( "since the above can't be factored, you must apply the \"quadratic formula\" to get: \n" ); document.write( "x = {8.51, -11.51} \n" ); document.write( "You can throw out the negative solution (extraneous) leaving: \n" ); document.write( "x = 8.51 \n" ); document.write( ". \n" ); document.write( "Details of quadratic follows: \n" ); document.write( "
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