document.write( "Question 466370: Solve the problem by setting up and solving an appropriate algebraic equation.
\n" ); document.write( "How many milliliters of pure acid must be added to 150 milliliters of a 40% solution of acid to obtain a 50% solution?\r
\n" ); document.write( "\n" ); document.write( "_________ml
\n" ); document.write( "

Algebra.Com's Answer #319717 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
How many milliliters of pure acid must be added to 150 milliliters of a 40% solution of acid to obtain a 50% solution?
\n" ); document.write( "---
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "1.00x + 0.40*150 = 0.50*(x+150)
\n" ); document.write( "---
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "100x + 40*150 = 40x + 50*150
\n" ); document.write( "60x = 10*150
\n" ); document.write( "---
\n" ); document.write( "x = (1/6)150
\n" ); document.write( "x = 50 ml (amt. of pure acid needed)
\n" ); document.write( "========================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "===============\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "_________ml\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );