document.write( "Question 466370: Solve the problem by setting up and solving an appropriate algebraic equation.
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document.write( "How many milliliters of pure acid must be added to 150 milliliters of a 40% solution of acid to obtain a 50% solution?\r
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document.write( "_________ml \n" );
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Algebra.Com's Answer #319717 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How many milliliters of pure acid must be added to 150 milliliters of a 40% solution of acid to obtain a 50% solution? \n" ); document.write( "--- \n" ); document.write( "acid + acid = acid \n" ); document.write( "1.00x + 0.40*150 = 0.50*(x+150) \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "100x + 40*150 = 40x + 50*150 \n" ); document.write( "60x = 10*150 \n" ); document.write( "--- \n" ); document.write( "x = (1/6)150 \n" ); document.write( "x = 50 ml (amt. of pure acid needed) \n" ); document.write( "======================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "===============\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "_________ml\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |