document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=465893>Question 465893</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Set up the necessary equation(s) and solve algebraically.\r<BR>\n" );
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document.write( "two numbers which differ by 3, have a product of 88. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #319705 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=319705\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p(p+3)=88<BR>\n" );
document.write( "p2+3p=88<BR>\n" );
document.write( "p2+3p-88=0<BR>\n" );
document.write( "(p+11)(p-8)=0<BR>\n" );
document.write( "p=-11 or 8<BR>\n" );
document.write( "Throwing out the negative answer, we get the two numbers to be 8 and 11.. </SPAN>\n" );
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