document.write( "Question 466352: THE PERIMETER OF A RECTANGLE IS 102 INCHES. THE LENGTH EXCEEDS THE WIDTH BY 9 INCHES. FIND THE LENGTH AND THE WIDTH \n" ); document.write( "

Algebra.Com's Answer #319692 by MathLover1(20849) $\"\"$ $\"About$

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the perimeter of rectangle is $\"P=2%28L%2BW%29\"$ \r
\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( " $\"P=102in\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"L=W%2B9in\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2%28L%2BW%29=102in\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2%28L%2BW%29%2F2=102in%2F2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"L%2BW=51in\"$ ..replace $\"L\"$ with $\"W%2B9in\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"W%2B9in%2BW=51in\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2W=51in-9in\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2W=42in\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2W%2F2=42in%2F2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"W=21in\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"L=W%2B9in\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"L=21in%2B9in\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"L=30in\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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