document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=466347>Question 466347</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The second angle of a triangle is 4 times as large as the first. The third angle is 45 degrees less than the sum of the other two angles. Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #319675 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=319675\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1st = x<BR>\n" );
document.write( "2nd = 4x<BR>\n" );
document.write( "3rd = x + 4x - 45<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "1st + 2nd + 3rd = 180<BR>\n" );
document.write( "x + 4x + 5x - 45 = 180<BR>\n" );
document.write( "10x = 135<BR>\n" );
document.write( "x = 22.5 degs<BR>\n" );
document.write( "1st = 22.5º<BR>\n" );
document.write( "2nd = 90º<BR>\n" );
document.write( "3rd = 67.5º<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );